英语周报2021-202261答案

解题导语】这是一篇说明文。文幸讲述了书香环境对于孩子成长的好处32B推理判断题。根据第二段中“ Radiation effect is a situationwhere children grow up around books, but they don't readbooks. But somehow books benefit then, even thoughthey don't read them as much as their parents wish themo”可知,辐射效应在本文中指在书香环境中长大的孩子虽然他们没有像父母期待的那样读那么多的书,但他们仍然从书中受益良多。由此推断出,书香环境对青少年的良好影响,故选B这A理判断题。根据第三段中“ If we grow up in a house,ina home where parents enjoy books, where books are givenas birthday presents and valued, this is something thatbecomes a part of our identity and gives us this lifelongurge to always come close to books and read more than we I则ld呵可知,如果我们生长在父母热爱书、珍惜书的家庭中,这将成为我们认知中的一部分,让我们终身都有接近书,多读书的渴望、故选A现点态度题,根据最后一段中“ So keep shelves piled with30y所以书柜里装满书吧,由此可知,作者对于书香环境是支持的,故选DsC主旨大意题,根据全文的大意,尤其是第一段中“weknow that reading is good for children. Now, a new studysuggests that just being around books has its benefits. "pJ,本文主要讲述了书香环境对孩子成长的好处。故选

24(什么e命题人考查带电粒子在电磁组合场中的运动、力的平衡、圆周运动、牛顿第二定律。么考(1)微粒从O点沿OP方向做直线运动的过程中,设微粒的质量为m,电量为q,微粒受力分析如图由几何关系可得mg=gE(1分)一mg=Bq(1分)解得磁感应强度的大小为:B=E=0.2T(2分)(2)电场方向变为竖直向上后电场力与重力平衡,微粒在洛伦兹力的作用下做匀圆周运动,Bq=m(2分)解得:r=1.6m(1分)画出的轨迹如图所示由轨迹可知,微粒在R点开始做国周运动,到达Q点磁场消失,微粒又做匀速直线运动回到O点,根据几何关系x=x00(1分)an6=-(2分)解得:x0n=xo°5m(1分)微粒做直线运动的路程为163x= XoR +xoo 5m(1分)

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