2019−2022英语周报高一课标答案

10.【答案】A解析】100m0.1 molL ICH3 COONa溶液中,m( CH3COONa)-0.01molA由于醋酸钠发生水解,溶液中含有醋酸根离子和少量水解生成的醋酸分子,根据物料守恒,CHCOO-和CH2COOH粒子总数为00NB.c(H)c(OH)=1×1014,则n(H)n(OH)=1×101412=1×1016,N(H+)MOH)=1×101N2;C』10omL水中,r(OH)=0.1L×10- molL-1=1×103mol,醋酸钠溶液中醋酸根离子,水解促进了水的电离,导致100m溶液中水电离产生的oH大于1×108ND.稀释溶液时,钠离子的物质的量不变,钠离子数目仍为001N

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