202216英语周报答案

书面表达One possible version:NOTICEA sports meeting will be held in the playground of our school from next Thursday to FridayAs you know, the pressure of study is very heavy now, especially for those senior 3. So the purpose of the sports meeting is to letevery student get relaxed, as a result of which we students can live happily and heal thilyEveryone is welcome to take part in it. Those who perform excellently at the sports meeting will get prizes. But don' t take theresults so serously because taking part is more important than the result. Good luck to everyone!

17.(1)H:C::C:H(2分)2)能耗低(或产物易分离,2分)(3)45(2分)(4)C2H(g)+CO2=C2H(g)+(O(g)+H2O(1)△H=+133.2kJ·mol-(2分);积碳能与CO2反应生成CO,从而脱离催化剂表面(2分)(5)氢气移出率增大,体系中氢气的浓度降低,平衡正向移动,乙烷的平衡转化率增大(2分);90%(2分)【解析】本题主要考查化学反应原理,考查学生对化学反应原理的理解能力和综合运用能力。HH(1)乙烯电子式为H:C::C:H(2)氧化裂解反应是放热反应,节约能源(3)因为总压恒定为100kPaC2H(g)2(2(g)C2H4(g)+HyO(g)平衡分压2.4%×100kPa4%×100kPa18%×100kPa12%×100kPa该温度下的平衡常数K2=486×10×12%×10045(kPa)(2.4%×100)×(4%×100)(4)由盖斯定律①一②+③得热化学方程式C2H(g)+CO2=C2H4(g)+CO(g)+H2O(1),则△H=(+136kJ·mol)-(-283.0kJ·mo-)+(-285.8kJ·mol-1)=+133.2k·mol-l;该工艺中碳与CO2反应生成CO,可以有效消除催化剂表面的积炭,维持催化剂活性(5)氢气移出率增大,生成物中氢气的浓度降低,有利于平衡正向移动,乙烷转化率增大;A点时乙烷的转化率为90%,生成H2的总物质的量为0.9mol,设平衡时体系中H2的物质的量为x,平衡体系中,c(乙烷)=0.1mo·-,c(乙烯)=0.9ml.1-,c(H1)=xmol·L,平衡常数K=0=0.,解得x0.09mol,则氢气移出率a≈=9.9-0.090.9×100%=90%

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