RX版英语周报10期2022答案

x=-4+22.解:(1)直线l的参数方程是消参,可得直线l的普通方程为x-3y+4=0由=4mi(3+)-3可得-45(20+1m)-36cos+2√3psin0-3将x=pos,y=psin0代入p2=6098+23 psin B-3,得x2+y=6x+2√3y-3即曲线C的直角坐标方程为(x-3)2+(y-3)2=-4+t,(2)点M恰好在直线l上,将代入(x-3)2+(y-√3)2=9中,化简整理得t2-8√3+43=0.设A,B两点对应的参数分别为1,2,则t1+t2=8√3,t1t2=43,所以点E对应的参数为,即|EM=/5+4√3.又曲线C是圆心为C(3,3),半径为3的圆,所以圆心C到直线l的距离d|3-3+42,所以动1+3点N到直线EM的最大距离为5,则△MNE面积的最大值是S=1×5×43=10

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