英语周报2018-20224答案

36(⑨(共15分,除标注外,其余每空2分)(1)取代反应(1分)2-氯丙酸(1分)(2)羧基、醚键H, C(3)<>Rr+2NaOHONa +NaBr+h,oH, C(4)5(1分-ONaCH HC(6NnOH乙醇CO(K:Hi,什么命题人考查有机推断与存机合成么考由流程图可知:A在催化剂作用下发生苯环上的溴代反应H3生成B,B发生取代反应生成C:+2MHH, C-ONa+NaBr+H1O,C发生已知1中的取代反应生成D,D发生已知Ⅱ屮的取代反应生成E,由E的结构反应条件,逆推D为H,CC为B为Brs对比E、F的结构,可知E中的羧基与碳酸钠反应E中的亚甲基与甲醛发生加成反应、消去反应引入碳碳双键,最终生成F。(4)2个甲基有邻、间、对3种位置结构,对应的一ONa分别有2种、3种、1种位置结构,共有6种,不包括C本身还有5种;核磁共振氡谱有3组峰,且峰面积之比为6:2:1的同分异构体的结构简式为CONa。(5) I mol F与足量NaCO溶液反应放出1 mo CO2,A项错误;E中含有羧基和羰基,可以发生加成反应和取代反应,B项正确;E中没有碳碳双键,也没有碳碳三键,不能通过加聚反应合成高分子化合物,C项错误;根据E的结构简式可知E的分子式为CHHO4,D项正确。(6)首先观察目标产物的结构该日标产物中含有六元环,结合“已知”反应可以推知,该目标产物可由二烯烃与碳碳双键发生加成反应得到。但其原料中只含有1个碳碳双键,所以要在该原料中再引入1个碳碳双键,可以通过卤代烃的消去反应来完成。则有BCOOCHYNaOH/乙醇COoCH△最后一步用氢气还原即可得到日标产物。

I looked at what the second man had dropped; it was jewellery. It all happened too quickly,but I soon realized what had happened. They were burglars. My friend Jeremy, who was waitingfor me, quickly ran out. when hearing unusual noises. We called the police and they were there 5minutes later. I gave the police officer descriptions of the thieves and told them the names theyhad called outYou were brave for trying stop them, "said the officer: We should be able to catch themwith your information. " Jeremy told the officer the owners of the house were on holiday and gavehim a phone number. When the officer left, I told Jeremy about the mistake with the doornumbers. I hadn, t really been brave at all, but my mix-up had stopped the burglars getting awaywith the jewelry. Jeremy's neighbor thanked me a lot when they came back. Actually I have been

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