初二英语周报第21期答案

读后续写Possible version lI stared at the paper and then looked around. I was cold. Although I could not see my sistersnor the new house, which was hidden from my sight by a grey wall, I got the feeling that I was notalone. Walking along the shore was a tall familiar figure who looked lost in his thoughts. I lookedgain at the paper in my hand, closed my eyes and wishedAs /opened my eyes, I found my father was standing right beside me. Happy birthday, sonhe said, patting my shoulder gently. I smiled up at him and took his hand. Looking back, life fromthat day on marked the start of a close bond and a strong friendship with my father. What was mybirthday surprise? Wishes do come truePossible version 2I stared at the paper and then looked around. On the backside, there was a map. I noticed thatit was clearly leading me in a direction, but who could have sent this? I stood there in silence andstudied it. I decided to follow the map and it led me down the beach until I reached a staircase. Iooked back and could no longer see my siblings. I continued to follow the point on the map, untilI unexpectedly lost my footing and fell zksq down the stepsAs I opened my eyes, I found my father was standing right beside me. Happy birthday, sonhe said, patting my shoulder gently. Then he asked how I had come upon this place? I explained tohim that I had found the bottle in the ocean and when I opened it had the words on it. Shocked bythe message, my father realized what I had found I threw this bottle into the ocean many years agowhen I was alone. he said. I used to come to this exact place to get away from everyone else. NowI get to share this experience with you. What a birthday surprise

22考查目标本题考查参数方程与普通方程的互化,求极坐标方程,考查逻辑推理和数学运算能力思路点拔(1)先将C1的参数方程化为晋通方程,结合极坐标和直角坐标的互化公式求出C1,然后再用极坐标系中求轨迹方程的方法求出C2的极坐标方程;(Ⅱ)先求出1O41,1OB1,然后利用面积公式和三角函数的知识求出B参考答案(1)出曲线C1的参数方程得Cn的普通方程为(x-1)2+y2=1()≥0),将x=posB,y=pinB代入上式得(ps0-1)2+p2sin6=1,化简得曲线C1的极坐标方程为p=2s(0≤6≤设曲线C1任意点的极坐标为(p6),则B=8+,B=B-所以C2的极坐标方程为p=20(6-)=2imB,即p=20(2≤n≤n)5(Ⅱ)将B=B代人C1得1OA1=p1=2sB将”=B+3代人2得1B1==2m(+票)由题意知8Aw=2,101:10m1m3cos Bin(B+3)(2mhB·2)(20-)÷由≤B<2得3≤2+3所以28+3=m解得B=3(10分)

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