2022英语周报高二牛津第40期答案

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x = cos C22解:(1)曲线C1的参数方程为根据cos2a=21消去参数α得曲线y=cos2的普通方程为y=2x2-1(0≤x≤1),(3分)由=(-<9<7),得曲线C2的直角坐标方程为y=xtan.(5分)(2)曲线C1及C2有公共点P,即直线y=xtanφ与抛物线y=2x2-1在[0,1]上的一段曲线有公共点P结合图象可知nφ≤1,-<≤丌,所以φ的取值范围是(-可,可],当OP|=2时,点P的直角坐标为(1,1),点P的极坐标为(2,可).(10分)

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