2018-2022 英语周报 高一 外研 31答案

第二节书面表达【写作思路】根据试题要求,考生需要写一篇记叙文,记述身边一位值得尊敬和爱戴的人。首先考生需要介绍自己最尊敬和爱戴的人是谁,简单地介绍一下他(她)。然后,陈述为什么他(她)值得尊敬和爱戴。最后,可以对前文进行一个总结,使文章结构严谨。本文的写作重点在"尊敬和爱戴的原因",考生可围绕这个要点适当拓展,从性格特点、处事风格等方面展开写作。【范文赏读】The most beloved and respected person around me is my teacher, Ms LiThough she has been teaching English for twenty years, she is still passionateabout teaching. She is kind and considerate towards us just like our dear motherWe all respect her because she always tries new ways to make her classes livelyand interesting. Hardworking and knowledgeable, she is one of the best teachersin our school. When we have a problem, we will turn to her for help. She alwaystalks to us patiently and helps us to find a solution. In our eyes, she is not onlyour teacher, but also our best friend. Those are why she deserves our respect【亮点词句】亮点词汇: beloved, respected, be passionate about, be consideratetowards, turn to sb. for help, in one's eyes亮点句式:Why引导的表语从句( why she deserves our respect)

18.解:(1)连接BC,交B1C于O,连接AO因为侧面BB1C1C为菱形,所以B1C⊥BC1,且O为B1C与BC1的中点又AB⊥B1C,所以B1C⊥平面ABO,故B1C⊥AO又B1O=CO,故AC=AB1即A:C=AB1(2)因为A1C1⊥AB1即AC⊥AB1,且O为B1C的中点所以AO=CO,又因为AB=BC,△BOA≌△BOC.故OA⊥OB,从而OA,OB,OB1两两垂直(6分)以O为坐标原点,的方向为x轴正方向,oB单位长,建立如图所示的空间直角坐标系Oxyz因为∠CBB1=60°,所以△CBB1为等边三角形又AB=BC则A(o2),B(1.,0),B1(020)c(不=(0.一)E一=(0.-)Cl√3设n=(x,y,z)是平面AA1B1的一个法向量,33z=0即n·A1B1=0,所以可取n=(1,33(9分)设m=(a,b,c)是平面A1B1C1的一个法向量,m·A1B1=m·B1C1=0,同理可取m=(1,-3,3).(11分)则c(n,:m)=团mm=7所以二面角A-A1B1-C1的余弦值为7·(12分)

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